Gidifans - Stories » Exams » Edu » Info Portal

GiDifans | June, 2018 | 7 | 596 |

Solution Centre for All Examinations both WAEC/WASSCE/SSCE, NECO, NABTEB, JAMB (UTME), Post-UTME, WAEC GCE, NECO GCE, NABTEB GCE etc

COMPLETED 1, 2, 3, 4, 6, 7, 9, 10, 12, 13, 14, 15, 17… BE UPDATED

Physics OBJ:

1BBBBAAEECD

11CCBCDDAADC

21EEACBAECAB

31EAAECEECBD

41AECCABEECE

51CEABBCABEB

Pease NOTE: You Are To Answer Six(6) QUESTION In Section A

While Four (4) QUESTIONS In Section B

1a)

water passes through a dam, and into a river below. The more water that passes through a dam, the more energy is produced. Once a dam is built, an artificial man-made lake is created behind the dam. Electricity is produced by a device called a turbine. Turbines contain metal coils surrounded by magnets. When the magnets spin over the metal coils, electricity is produced. Turbines are located inside dams. The falling water spins the magnets.

1b)

Given:

M=10

U=?

V=mu

F=+5cm

V=10u(virtual image)

using the real is positive convention

1/f=1/u+1/v

1/5=1/u-1/10u

1/5=10-1/10u

1/5=9/10u

10u=45

u=45/10

u=4.5cm

the object must be placed 4.5cm from the microscope.

2)

the distance covered S by a body with initail speed U and final speed V in time t is

distance = average speed x time

S = (u+v/2)t

first equation

acceleration = change in velocity/time

a=v-u/t

v-u=at

v=u+at

putting the first equation into S = (u+v/2)t we have

S = (u+u+at/2)t

S = (2u+at/2)t

S = (u+at/2/2)t

S = ut+1/2at^2

this is the second equation

3a)

i)contact forces

ii)field forces

3b)

Time taken for ball to fall is the same as when the ball is dropped from that height

Hence:

u=omls

h=20m

g=10mls^2

t=?

Using:

h=ut + 1/29t^2

20=0(t)+1/2(10)t^2

20=5t^2

5t^2=20

t^2=20/5

t^2=4

t=√4

t=2secs

time taken for ball to fall to the ground = 2secs

4)

The energy posses by a moving car is kinetic energy and is possessed when in motion while the energy possessed by a stationary car on a hold is potential energy and is possessed when at rest due to a confirm height

4b)

Elastic potential energy

6a)

the incident ray, the reflected ray and the normal at the point of incidence all lie in the same plane

6b)

i)diverging lens

ii)the diverge light rays entering the eye from a distance object and make them appear to be coming from the person far point

7a)

i)used in car headlamps

ii)used as a shaving mirror

given

object distance U =13cm

image distance V = -4cm

focal length F = ?

Using the real is positive convention

1/f=1/u+1/v

1/f=1/13-1/4

1/f=4-13/52

1/f= -9/52

f= -52/9= -5.8cm

9a)

i)cross sectional area of plates

ii)distanace between plates

9b)

Given:

M=6kg

D=3m

G=6.67*10^-11 Nm^2kg^-2

using:

F= Gm^2/d^2

F= 6.667*10^-11*6^2/3^2

F= 2.668*10^-10N

10a)

i)Mercury dropped on glass from droplets because the cohesion of mercury is stronger than it adhesion

ii)Water rise in capillary tube because the force of adhesion at water molecules with glass is greater than their cohesion to each other.

10b)

Surface tension, the ability of water to behave an elastic skin make it possible for an insect to crawl on water

12ai)

A trajectory is the path traced by a projectile

12aii)

I)the fired bullet

ii)thrown javelin

iii)thrown bomb

12b)

i)A scalar quantity has no direction while vector quantity has direction

ii)Scalars can be added and subtracted easily by using ordinary algebra while vector quantity however have to be added or subtracted by vector diagrams and law like parallelogram,triangle law and resolution of vectors.

12ci)

CLICK HERE FOR THE DIAGRAM

12cii)

I) from the diagram

slope Bc = CD/BD

14=(V-20)/20

V-20=280

V=280+20

Final velocity V=300mls

II)Total distance= Area of rectangle OABFO+Area Of Trapezium FBCEF

=(OA*OF) + [1/2(BF+CE)FE]

=(20*40) + [1/2(20+300)20]

=800+3200

=400metres

14a)

The law of reflection state that the angle which the incident ray makes with the normal is equal to the angle which the reflected ray makes to the same normal.

14b)

i)Effect of density

ii)Effect of temperature:- In a gas.

14d)

using the lens formula

1/f=1/u+1/v

1/5=1/6+1/v

1/5-1/6=1/v

6-5/30=1/v

1/30=1/v

V=30cm (image distance from lens)

Total distance between image of len And image of mirror is

=30+12+16

=48cm

CLICK HERE FOR THE IMAGE

13a)

Specific heat capacity can be defined as the quantity of heat required to raise a unit mass of a material by one kelvin(k) or degrees Celsius(‘C)

13aii)

i)change in temperature of phase/State

ii)Change in resistance and in colour.

13aiii)

i)Linear expansivity results to expansion of metals or concrete bridges.

ii)It as well causes cracking of glass cup when hot water is poured into the glass cup.

13b)

i)Heat is nothing but the amount of energy in a body. As against this, temperature is something that measures the intensity of heat.

ii)Heat measures both kinetic and potential energy contained by molecules in an object. On the other hand, temperature measures average kinetic energy of molecules in substance.

iii)The main feature of heat is that it travels from hotter region to cooler region. Unlike temperature, which rises when heated and falls when cooled.

13ci)

when an inflated ballon is pierced and eleased, it obeys newton’s third law of motion. Air rushes out from the pierced hole and the balloon moves in the opposite direction

13cii)

Jet

13d)

using [email protected] [email protected]

Given [email protected] [email protected]=(25-20)=5degree

Cx=1/2CY

then Mx[1/2CY]=MYCY

Mx/My=Cy/1/2Cy

Mx/My=2

Ratio of mass Of X to Y is 2:1

15ai)

Force field is a region around a body in which it experiences an effect (force) due to the presence of another body

15aii)

i)gravitational field

ii)magnetic field

15b)

Show that the escape velocity(Ve) of an object from the earth surface is √2Gme/r

To prove the escape velocity (Ve) of an object from the earth surface we can say let the kinetic energy of the object of mass M is

Ek=1/2MVe^2

When an object is at any given point P which is at a distance X from the centre of the earth the force of unity between the object and earth is

F=Gmm/X^2

Work done is taken the body against gravitational attraction DW=Fdx=Gmm/X^2 DX

Where W=work done in taking the body against gravitational attraction

W={R DW= {R Gmm/X^2 DM

=Gmm {R X^2 DM = Gmm [X^2/Y {R

= -Gmm [1/X]R = – Gmm [1/~ – 1/R]

Or, W=Gmm/R

For the object to escape from the earth surface

Ek=workdone,W

Ek=W

1/2MVe=Gmm/R

Ve=√2Gm/R(proved)

15ci)

i)Power supply smoothing applications

ii)RF coupling or filter capacitor applications

15cii)

Data given

d =4mm=4*10^-3 , 0.004m

A= 0.2m^2, V=300V

[Eo=8.85*10^-12fm^-1]

i)capacitance of the capacitor

using the approprate formula

C=EoAv/d

C=8.85*10^-12*0.2*200/0.004

C=8.85*10^-12*2*10^-1*2*10^2/4*10^3

C= 35.4*10^-11/4*10^-3

C= 8.85*10^-10^-11+3

C=8.85*10^-8F

the capacitance of the capacitor is 8.85*10^-8F

ii)Electric Field intensity between the plates

E=F/q =K.q.d/d^2/q

E=kQ/d^2

E=8.85*10^-12*Q/d^2

but Q=CV

Q=8.85*10^-8*2*10^2

Q=17.7*10^-6 C,1.77*10^-7C

E=8.85*10^-12*1.77*10^-7/(4*10^-3)^2

E=15.7*10^-19/16*10^-6

E=1.57*10^-20/1.6*10^-5

E=0.98*10^-15

E=9.8*10^-1*10^-15

E=9.8*10^-16N|C or E=9.8*10^-16NC

the electric field intensity have the plates is 9.8*10^-16 NC

17a)

i)Stay on top of large machinery operator training

ii)Keep large machinery clean, and maintain a clean environment

17bi)

-Compound Microsoft-

for viewing samples at high magnification (40 – 1000x), which is achieved by the combined effect of two sets of lenses: the ocular lens (in the eyepiece) and the objective lenses

17bii)

-Film projector-

an optical device that projects an image (or moving images) onto a surface, commonly a projection screen.

17c)

Artificial satellite orbits the earth and observes it. A rocket is designed to go to different planets, either taking people with it, or taking a space prob to take pictures of that planet.

17d)

data given

Rg=5n,Ig=10mA Vg=40V Rx=?

Ig=10mA =10*10^-3A

Ig=10^-2A

For Conversion Of galvanometer into voltmeter.

Vg=Ig(Rg+Rx)

Vg=Ig Rg + Ig Rx

Vg-Ig Rg =Ig Rx

Rx=Vg-IgRg/Ig

Rx=Vg/Ig-Rg

=40/10^-2 – 5/1

Rx=40/0.01 – 5/1

Rx=40-0.05/0.01

Rx=39.95/0.01

Rx=3995

the resistance of resistor is 3995

also don't forget to leave a Reply, we would very MUCH appreciate Your Comments On This Post Below. Thanks!

Related » Gidifans Examination Center (GEC)

6112

Thank you for your effort.

i need physics obj

tnks

Thanks,for your hels

Thanks,for your help

Weldon more gwrist to ur elbow